Code Optimization: Effective Memory Usage by Kris Kaspersky

By Kris Kaspersky

A advisor to optimizing courses at the computer and Unix systems, this ebook covers the expediency of optimization and the easy methods to raise the rate of courses through optimization. mentioned are common error made through programmers that decrease the functionality of the procedure in addition to simply applied recommendations. precise descriptions of the units and mechanism of interplay of the pc parts, potent methods of programming, and a method for optimizing courses, are supplied. Programmers also will methods to successfully enforce programming tools in a high-level language that's often performed in assembler with specific realization given to the RAM subsystem. The operating rules of the RAM and how during which it really is coupled with the processor in addition to an outline of programming tools that permits programmers to overclock the reminiscence to arrive greatest functionality are integrated.

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Pswd[p]) { pswd[p] = ' '; pswd[p+1]=0; length++; } }; p = 0; } return 0; } 40 Chapter 1: Program Profiling Chapter 1: Program Profiling 41 Compile and start the redesigned program. You may not believe your eyes — now you have achieved a speed of 35 million passwords per second. Before this, it seemed that there were no more performance reserves. Now, who would dare say that Pentium is a slow processor? The generation of the next password, its checking, and the calculation of its CRC take about 20 clocks.

36: Instructions Residing at the Offsets Specified by VTune 1:55 1:72 mov ebp, DWORD PTR [esp+018h] mov DWORD PTR [esp+010h], ecx Despite the visible difference in operands, they address the same variable because there are two PUSH machine commands between them. These commands decrease the value of the ESP register by 8. Thus, this assumption is correct, and you can confirm it by clicking the Apply button. Now, concentrate on the instructions in gray (in Fig. 10) and marked with traffic lights.

Presumably, this is an error by the Coach. ) However, consider the example provided by the Coach. Perhaps, there is a misunderstanding. 34: Example Provided by the Coach for the Third Tip Original Code int b[200] [120]; void xmp117(int *a) { int i, j; for (i = 0; i < 120; i++) for (j = 0; j < 200; j++) b[j] [i]=b[j] [i]+a[2*j]; } | | | | | | | | | | | | Optimized Code int b[200] [120]; void ymp117(int *a) { int i, j; int atemp; for (j = 0; j < 200; j++) for (i = 0; i < 120; i++) b[j] [i]=b[j] [i]+a[2*j]; } Well, this is correct.

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